test-repo/changelog_unreleased/javascript/10187.md at 1501ea49793dcda4a1fac009580eb0eeefa99c5a

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Sosuke Suzukiandfisker Cheung 7d84c0a5a4 Fix inconsistent indentation for ternary in call expressions (#10266 )

* Refactor with do while

* return false when ternary in CallExpression is not callee

* Update changelog

* For computed member property

* Fix

* Simplify

* Minor tweak

Co-authored-by: fisker Cheung <lionkay@gmail.com>

2021-02-12 08:11:24 +09:00

2.2 KiB

Raw Blame History

Consistent indentations for conditional operators (#10187, #10266 by @sosukesuzuki)

// Input
const dotNotationMemberExpression = (
  callNode.parent?.type === AST_NODE_TYPES.ChainExpression
    ? callNode.parent.parent
    : callNode.parent
).TSESTree.BinaryExpression;
const computedMemberExpression = (
  callNode.parent?.type === AST_NODE_TYPES.ChainExpression
    ? callNode.parent.parent
    : callNode.parent
)[TSESTree.BinaryExpression];
const callExpressionCallee = (
  callNode.parent?.type === AST_NODE_TYPES.ChainExpression
    ? callNode.parent.parent
    : callNode.parent
)(TSESTree.BinaryExpression);
const typeScriptAsExpression = (
  callNode.parent?.type === AST_NODE_TYPES.ChainExpression
    ? callNode.parent.parent
    : callNode.parent
) as TSESTree.BinaryExpression;

// Prettier stable
const dotNotationMemberExpression = (callNode.parent?.type ===
AST_NODE_TYPES.ChainExpression
  ? callNode.parent.parent
  : callNode.parent
).TSESTree.BinaryExpression;
const computedMemberExpression = (callNode.parent?.type ===
AST_NODE_TYPES.ChainExpression
  ? callNode.parent.parent
  : callNode.parent)[TSESTree.BinaryExpression];
const callExpressionCallee = (callNode.parent?.type ===
  AST_NODE_TYPES.ChainExpression
  ? callNode.parent.parent
  : callNode.parent)(TSESTree.BinaryExpression);
const typeScriptAsExpression = (callNode.parent?.type ===
AST_NODE_TYPES.ChainExpression
  ? callNode.parent.parent
  : callNode.parent) as TSESTree.BinaryExpression;

// Prettier main
const dotNotationMemberExpression = (
  callNode.parent?.type === AST_NODE_TYPES.ChainExpression
    ? callNode.parent.parent
    : callNode.parent
).TSESTree.BinaryExpression;
const computedMemberExpression = (
  callNode.parent?.type === AST_NODE_TYPES.ChainExpression
    ? callNode.parent.parent
    : callNode.parent
)[TSESTree.BinaryExpression];
const callExpressionCallee = (
  callNode.parent?.type === AST_NODE_TYPES.ChainExpression
    ? callNode.parent.parent
    : callNode.parent
)(TSESTree.BinaryExpression);
const typeScriptAsExpression = (
  callNode.parent?.type === AST_NODE_TYPES.ChainExpression
    ? callNode.parent.parent
    : callNode.parent
) as TSESTree.BinaryExpression;

2.2 KiB Raw Blame History

Consistent indentations for conditional operators (#10187, #10266 by @sosukesuzuki)

2.2 KiB

Raw Blame History